Base | Representation |
---|---|
bin | 1001000110110110110100… |
… | …0111101001011011110111 |
3 | 1022110021100000201210010212 |
4 | 2101231231013221123313 |
5 | 2303024420232110442 |
6 | 33144031530340035 |
7 | 2052305242202561 |
oct | 221555507513367 |
9 | 38407300653125 |
10 | 10013399488247 |
11 | 3210727a64951 |
12 | 11587b728a61b |
13 | 57834b21c8ac |
14 | 268918968331 |
15 | 1257114a6a82 |
hex | 91b6d1e96f7 |
10013399488247 has 2 divisors, whose sum is σ = 10013399488248. Its totient is φ = 10013399488246.
The previous prime is 10013399488217. The next prime is 10013399488249. The reversal of 10013399488247 is 74288499331001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10013399488247 is a prime.
It is a super-2 number, since 2×100133994882472 (a number of 27 digits) contains 22 as substring.
Together with 10013399488249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10013399488249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006699744123 + 5006699744124.
It is an arithmetic number, because the mean of its divisors is an integer number (5006699744124).
Almost surely, 210013399488247 is an apocalyptic number.
10013399488247 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013399488247 is an equidigital number, since it uses as much as digits as its factorization.
10013399488247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10450944, while the sum is 59.
The spelling of 10013399488247 in words is "ten trillion, thirteen billion, three hundred ninety-nine million, four hundred eighty-eight thousand, two hundred forty-seven".
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