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100134000151 = 1734667169909
BaseRepresentation
bin101110101000001110…
…0111001011000010111
3100120110111210020220021
41131100130321120113
53120033301001101
6114000111050011
710143261646333
oct1352034713027
9316414706807
10100134000151
113951503a429
12174a6810907
13959a4c8b83
144bbcb827c3
152910da85a1
hex1750739617

100134000151 has 8 divisors (see below), whose sum is σ = 106027917840. Its totient is φ = 94240491648.

The previous prime is 100134000119. The next prime is 100134000157. The reversal of 100134000151 is 151000431001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100134000151 - 25 = 100134000119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100134000157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 504385 + ... + 674293.

It is an arithmetic number, because the mean of its divisors is an integer number (13253489730).

Almost surely, 2100134000151 is an apocalyptic number.

100134000151 is a deficient number, since it is larger than the sum of its proper divisors (5893917689).

100134000151 is a wasteful number, since it uses less digits than its factorization.

100134000151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204593.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 100134000151 its reverse (151000431001), we get a palindrome (251134431152).

The spelling of 100134000151 in words is "one hundred billion, one hundred thirty-four million, one hundred fifty-one", and thus it is an aban number.

Divisors: 1 17 34667 169909 589339 2888453 5890235303 100134000151