Base | Representation |
---|---|
bin | 10010101001101100… |
… | …01001001110100111 |
3 | 221211212000011002201 |
4 | 21110312021032213 |
5 | 131001413224221 |
6 | 4333342115331 |
7 | 503066421505 |
oct | 112466111647 |
9 | 27755004081 |
10 | 10013414311 |
11 | 427934741a |
12 | 1b3557bb47 |
13 | c37706134 |
14 | 6adc55675 |
15 | 3d915c891 |
hex | 254d893a7 |
10013414311 has 4 divisors (see below), whose sum is σ = 10068737224. Its totient is φ = 9958091400.
The previous prime is 10013414293. The next prime is 10013414351. The reversal of 10013414311 is 11341431001.
10013414311 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10013414311 - 217 = 10013283239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10013414351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27661185 + ... + 27661546.
It is an arithmetic number, because the mean of its divisors is an integer number (2517184306).
Almost surely, 210013414311 is an apocalyptic number.
10013414311 is a deficient number, since it is larger than the sum of its proper divisors (55322913).
10013414311 is an equidigital number, since it uses as much as digits as its factorization.
10013414311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55322912.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 10013414311 its reverse (11341431001), we get a palindrome (21354845312).
The spelling of 10013414311 in words is "ten billion, thirteen million, four hundred fourteen thousand, three hundred eleven".
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