Base | Representation |
---|---|
bin | 10110110001001001010000… |
… | …110101011110010110010011 |
3 | 111010112201221012221200221011 |
4 | 112301021100311132112103 |
5 | 101111044342233443123 |
6 | 552545005523111351 |
7 | 30043313261101333 |
oct | 2661112065362623 |
9 | 433481835850834 |
10 | 100134223734163 |
11 | 299a675a8932a3 |
12 | b292824b12557 |
13 | 43b48030b6458 |
14 | 1aa27452310c3 |
15 | b89ac334ee0d |
hex | 5b1250d5e593 |
100134223734163 has 2 divisors, whose sum is σ = 100134223734164. Its totient is φ = 100134223734162.
The previous prime is 100134223734121. The next prime is 100134223734203. The reversal of 100134223734163 is 361437322431001.
It is an a-pointer prime, because the next prime (100134223734203) can be obtained adding 100134223734163 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100134223734163 - 241 = 97935200478611 is a prime.
It is not a weakly prime, because it can be changed into another prime (100134223734113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50067111867081 + 50067111867082.
It is an arithmetic number, because the mean of its divisors is an integer number (50067111867082).
Almost surely, 2100134223734163 is an apocalyptic number.
100134223734163 is a deficient number, since it is larger than the sum of its proper divisors (1).
100134223734163 is an equidigital number, since it uses as much as digits as its factorization.
100134223734163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 40.
The spelling of 100134223734163 in words is "one hundred trillion, one hundred thirty-four billion, two hundred twenty-three million, seven hundred thirty-four thousand, one hundred sixty-three".
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