100135121 has 2 divisors, whose sum is σ = 100135122. Its totient is φ = 100135120.

The previous prime is 100135109. The next prime is 100135127. The reversal of 100135121 is 121531001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55726225 + 44408896 = 7465^2 + 6664^2 .

It is an emirp because it is prime and its reverse (121531001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100135121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100135096 and 100135105.

It is not a weakly prime, because it can be changed into another prime (100135127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50067560 + 50067561.

It is an arithmetic number, because the mean of its divisors is an integer number (50067561).

Almost surely, 2^100135121 is an apocalyptic number.

It is an amenable number.

100135121 is a deficient number, since it is larger than the sum of its proper divisors (1).

100135121 is an equidigital number, since it uses as much as digits as its factorization.

100135121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 100135121 is about 10006.7537693300. The cubic root of 100135121 is about 464.3678479794.

Adding to 100135121 its reverse (121531001), we get a palindrome (221666122).

The spelling of 100135121 in words is "one hundred million, one hundred thirty-five thousand, one hundred twenty-one".