10014111312221 has 4 divisors (see below), whose sum is σ = 10203056808732. Its totient is φ = 9825165815712.

The previous prime is 10014111312209. The next prime is 10014111312277. The reversal of 10014111312221 is 12221311141001.

It is a happy number.

10014111312221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3705278508100 + 6308832804121 = 1924910^2 + 2511739^2 .

It is a cyclic number.

It is not a de Polignac number, because 10014111312221 - 2³⁸ = 9739233405277 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10014111312193 and 10014111312202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10014111312281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94472748176 + ... + 94472748281.

It is an arithmetic number, because the mean of its divisors is an integer number (2550764202183).

Almost surely, 2^{10014111312221} is an apocalyptic number.

It is an amenable number.

10014111312221 is a deficient number, since it is larger than the sum of its proper divisors (188945496511).

10014111312221 is an equidigital number, since it uses as much as digits as its factorization.

10014111312221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188945496510.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 10014111312221 its reverse (12221311141001), we get a palindrome (22235422453222).

The spelling of 10014111312221 in words is "ten trillion, fourteen billion, one hundred eleven million, three hundred twelve thousand, two hundred twenty-one".