10014302113 has 4 divisors (see below), whose sum is σ = 10014668820. Its totient is φ = 10013935408.

The previous prime is 10014302101. The next prime is 10014302119. The reversal of 10014302113 is 31120341001.

10014302113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31120341001 = 149 ⋅208861349.

It can be written as a sum of positive squares in 2 ways, for example, as 6766214049 + 3248088064 = 82257^2 + 56992^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10014302113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10014302119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138778 + ... + 198211.

It is an arithmetic number, because the mean of its divisors is an integer number (2503667205).

Almost surely, 2^10014302113 is an apocalyptic number.

It is an amenable number.

10014302113 is a deficient number, since it is larger than the sum of its proper divisors (366707).

10014302113 is an equidigital number, since it uses as much as digits as its factorization.

10014302113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 366706.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10014302113 its reverse (31120341001), we get a palindrome (41134643114).

The spelling of 10014302113 in words is "ten billion, fourteen million, three hundred two thousand, one hundred thirteen".