10020011002013 has 2 divisors, whose sum is σ = 10020011002014. Its totient is φ = 10020011002012.

The previous prime is 10020011001997. The next prime is 10020011002019. The reversal of 10020011002013 is 31020011002001.

10020011002013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8535407657764 + 1484603344249 = 2921542^2 + 1218443^2 .

It is a cyclic number.

It is not a de Polignac number, because 10020011002013 - 2⁴ = 10020011001997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10020011001985 and 10020011002003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10020011002019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010005501006 + 5010005501007.

It is an arithmetic number, because the mean of its divisors is an integer number (5010005501007).

Almost surely, 2^{10020011002013} is an apocalyptic number.

It is an amenable number.

10020011002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020011002013 is an equidigital number, since it uses as much as digits as its factorization.

10020011002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Subtracting from 10020011002013 its product of nonzero digits (12), we obtain a palindrome (10020011002001).

Adding to 10020011002013 its reverse (31020011002001), we get a palindrome (41040022004014).

The spelling of 10020011002013 in words is "ten trillion, twenty billion, eleven million, two thousand, thirteen".