Base | Representation |
---|---|
bin | 11101001010011000000… |
… | …10000110101010010001 |
3 | 10112210100022102100212111 |
4 | 32211030002012222101 |
5 | 112404100231444303 |
6 | 2044151441425321 |
7 | 132251365654024 |
oct | 16451402065221 |
9 | 3483308370774 |
10 | 1002002999953 |
11 | 356a4663145a |
12 | 14224093b241 |
13 | 73647253507 |
14 | 366d64831bb |
15 | 1b0e751cb6d |
hex | e94c086a91 |
1002002999953 has 2 divisors, whose sum is σ = 1002002999954. Its totient is φ = 1002002999952.
The previous prime is 1002002999951. The next prime is 1002002999971. The reversal of 1002002999953 is 3599992002001.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 675999684864 + 326003315089 = 822192^2 + 570967^2 .
It is a cyclic number.
It is not a de Polignac number, because 1002002999953 - 21 = 1002002999951 is a prime.
Together with 1002002999951, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1002002999897 and 1002002999906.
It is not a weakly prime, because it can be changed into another prime (1002002999951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501001499976 + 501001499977.
It is an arithmetic number, because the mean of its divisors is an integer number (501001499977).
Almost surely, 21002002999953 is an apocalyptic number.
It is an amenable number.
1002002999953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002002999953 is an equidigital number, since it uses as much as digits as its factorization.
1002002999953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 393660, while the sum is 49.
The spelling of 1002002999953 in words is "one trillion, two billion, two million, nine hundred ninety-nine thousand, nine hundred fifty-three".
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