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10020042013 is a prime number
BaseRepresentation
bin10010101010011110…
…11011010100011101
3221212022110212121011
421111033123110131
5131010112321023
64334140135221
7503206644322
oct112517332435
927768425534
1010020042013
114282063963
121b37837511
13c38bb6a57
146b0a9cb49
153d9a1b50d
hex2553db51d

10020042013 has 2 divisors, whose sum is σ = 10020042014. Its totient is φ = 10020042012.

The previous prime is 10020042007. The next prime is 10020042017. The reversal of 10020042013 is 31024002001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9489292569 + 530749444 = 97413^2 + 23038^2 .

It is a cyclic number.

It is not a de Polignac number, because 10020042013 - 29 = 10020041501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10020041984 and 10020042002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10020042017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010021006 + 5010021007.

It is an arithmetic number, because the mean of its divisors is an integer number (5010021007).

Almost surely, 210020042013 is an apocalyptic number.

It is an amenable number.

10020042013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020042013 is an equidigital number, since it uses as much as digits as its factorization.

10020042013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 10020042013 its reverse (31024002001), we get a palindrome (41044044014).

The spelling of 10020042013 in words is "ten billion, twenty million, forty-two thousand, thirteen".