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10020110035 = 5131092575503
BaseRepresentation
bin10010101010011111…
…01011111011010011
3221212022121022220111
421111033223323103
5131010122010120
64334141422151
7503210346535
oct112517537323
927768538814
1010020110035
1142820aaa81
121b3786a957
13c38c0b9c0
146b0ab9855
153d9a3175a
hex2553ebed3

10020110035 has 32 divisors (see below), whose sum is σ = 13121095680. Its totient is φ = 7301726208.

The previous prime is 10020109999. The next prime is 10020110069. The reversal of 10020110035 is 53001102001.

It is a cyclic number.

It is not a de Polignac number, because 10020110035 - 217 = 10019978963 is a prime.

It is a super-2 number, since 2×100201100352 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a junction number, because it is equal to n+sod(n) for n = 10020109997 and 10020110024.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1818094 + ... + 1823596.

It is an arithmetic number, because the mean of its divisors is an integer number (410034240).

Almost surely, 210020110035 is an apocalyptic number.

10020110035 is a deficient number, since it is larger than the sum of its proper divisors (3100985645).

10020110035 is a wasteful number, since it uses less digits than its factorization.

10020110035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5887.

The product of its (nonzero) digits is 30, while the sum is 13.

Adding to 10020110035 its reverse (53001102001), we get a palindrome (63021212036).

The spelling of 10020110035 in words is "ten billion, twenty million, one hundred ten thousand, thirty-five".

Divisors: 1 5 13 65 109 257 545 1285 1417 3341 5503 7085 16705 27515 28013 71539 140065 357695 364169 599827 1414271 1820845 2999135 7071355 7797751 18385523 38988755 91927615 154155539 770777695 2004022007 10020110035