Base | Representation |
---|---|
bin | 10010101010011111… |
… | …01011111011010011 |
3 | 221212022121022220111 |
4 | 21111033223323103 |
5 | 131010122010120 |
6 | 4334141422151 |
7 | 503210346535 |
oct | 112517537323 |
9 | 27768538814 |
10 | 10020110035 |
11 | 42820aaa81 |
12 | 1b3786a957 |
13 | c38c0b9c0 |
14 | 6b0ab9855 |
15 | 3d9a3175a |
hex | 2553ebed3 |
10020110035 has 32 divisors (see below), whose sum is σ = 13121095680. Its totient is φ = 7301726208.
The previous prime is 10020109999. The next prime is 10020110069. The reversal of 10020110035 is 53001102001.
It is a cyclic number.
It is not a de Polignac number, because 10020110035 - 217 = 10019978963 is a prime.
It is a super-2 number, since 2×100201100352 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is a junction number, because it is equal to n+sod(n) for n = 10020109997 and 10020110024.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1818094 + ... + 1823596.
It is an arithmetic number, because the mean of its divisors is an integer number (410034240).
Almost surely, 210020110035 is an apocalyptic number.
10020110035 is a deficient number, since it is larger than the sum of its proper divisors (3100985645).
10020110035 is a wasteful number, since it uses less digits than its factorization.
10020110035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5887.
The product of its (nonzero) digits is 30, while the sum is 13.
Adding to 10020110035 its reverse (53001102001), we get a palindrome (63021212036).
The spelling of 10020110035 in words is "ten billion, twenty million, one hundred ten thousand, thirty-five".
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