100201210000001 has 4 divisors (see below), whose sum is σ = 109310410909104. Its totient is φ = 91092009090900.

The previous prime is 100201209999991. The next prime is 100201210000013. The reversal of 100201210000001 is 100000012102001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100201210000001 - 2³⁴ = 100184030130817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100201210000301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4554600454535 + ... + 4554600454556.

It is an arithmetic number, because the mean of its divisors is an integer number (27327602727276).

Almost surely, 2^{100201210000001} is an apocalyptic number.

100201210000001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

100201210000001 is a deficient number, since it is larger than the sum of its proper divisors (9109200909103).

100201210000001 is an equidigital number, since it uses as much as digits as its factorization.

100201210000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9109200909102.

The product of its (nonzero) digits is 4, while the sum is 8.

Adding to 100201210000001 its reverse (100000012102001), we get a palindrome (200201222102002).

The spelling of 100201210000001 in words is "one hundred trillion, two hundred one billion, two hundred ten million, one", and thus it is an aban number.