10020121212113 has 4 divisors (see below), whose sum is σ = 10050393481968. Its totient is φ = 9989848942260.

The previous prime is 10020121212109. The next prime is 10020121212137. The reversal of 10020121212113 is 31121212102001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10020121212113 - 2² = 10020121212109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10020121212091 and 10020121212100.

It is not an unprimeable number, because it can be changed into a prime (10020121212193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15136134431 + ... + 15136135092.

It is an arithmetic number, because the mean of its divisors is an integer number (2512598370492).

Almost surely, 2^{10020121212113} is an apocalyptic number.

It is an amenable number.

10020121212113 is a deficient number, since it is larger than the sum of its proper divisors (30272269855).

10020121212113 is an equidigital number, since it uses as much as digits as its factorization.

10020121212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30272269854.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10020121212113 its reverse (31121212102001), we get a palindrome (41141333314114).

The spelling of 10020121212113 in words is "ten trillion, twenty billion, one hundred twenty-one million, two hundred twelve thousand, one hundred thirteen".