100201311332023 has 4 divisors (see below), whose sum is σ = 109310521453128. Its totient is φ = 91092101210920.

The previous prime is 100201311331999. The next prime is 100201311332039. The reversal of 100201311332023 is 320233113102001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100201311332023 - 2⁵ = 100201311331991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100201311331985 and 100201311332003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100201311332123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4554605060536 + ... + 4554605060557.

It is an arithmetic number, because the mean of its divisors is an integer number (27327630363282).

Almost surely, 2^{100201311332023} is an apocalyptic number.

100201311332023 is a deficient number, since it is larger than the sum of its proper divisors (9109210121105).

100201311332023 is an equidigital number, since it uses as much as digits as its factorization.

100201311332023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9109210121104.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 100201311332023 its reverse (320233113102001), we get a palindrome (420434424434024).

The spelling of 100201311332023 in words is "one hundred trillion, two hundred one billion, three hundred eleven million, three hundred thirty-two thousand, twenty-three".