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100201313011 = 175894194883
BaseRepresentation
bin101110101010001110…
…1101011001011110011
3100120122012110002210011
41131110131223023303
53120203014004021
6114010513515351
710145040051622
oct1352435531363
9316565402704
10100201313011
113954a035598
1217505272b57
1395ab436577
144bc7aa56b9
152916c52de1
hex175476b2f3

100201313011 has 4 divisors (see below), whose sum is σ = 106095507912. Its totient is φ = 94307118112.

The previous prime is 100201312951. The next prime is 100201313027. The reversal of 100201313011 is 110313102001.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 100201313011 - 29 = 100201312499 is a prime.

It is a super-2 number, since 2×1002013130112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100201312982 and 100201313000.

It is not an unprimeable number, because it can be changed into a prime (100201313081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2947097425 + ... + 2947097458.

It is an arithmetic number, because the mean of its divisors is an integer number (26523876978).

Almost surely, 2100201313011 is an apocalyptic number.

100201313011 is a deficient number, since it is larger than the sum of its proper divisors (5894194901).

100201313011 is an equidigital number, since it uses as much as digits as its factorization.

100201313011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5894194900.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100201313011 its reverse (110313102001), we get a palindrome (210514415012).

The spelling of 100201313011 in words is "one hundred billion, two hundred one million, three hundred thirteen thousand, eleven".

Divisors: 1 17 5894194883 100201313011