Base | Representation |
---|---|
bin | 101110101010010000… |
… | …1000110111011111000 |
3 | 100120122021010211111020 |
4 | 1131110201012323320 |
5 | 3120203231304422 |
6 | 114010545102440 |
7 | 10145050521051 |
oct | 1352441067370 |
9 | 316567124436 |
10 | 100202213112 |
11 | 3954a59a881 |
12 | 17505627a20 |
13 | 95ab690181 |
14 | 4bc7c5b728 |
15 | 2916d7e95c |
hex | 1754846ef8 |
100202213112 has 64 divisors (see below), whose sum is σ = 260641908000. Its totient is φ = 32062539264.
The previous prime is 100202213101. The next prime is 100202213113. The reversal of 100202213112 is 211312202001.
It is a junction number, because it is equal to n+sod(n) for n = 100202213091 and 100202213100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100202213113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 295687 + ... + 536502.
Almost surely, 2100202213112 is an apocalyptic number.
100202213112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
100202213112 is an abundant number, since it is smaller than the sum of its proper divisors (160439694888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100202213112 is a wasteful number, since it uses less digits than its factorization.
100202213112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 832400 (or 832396 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 100202213112 its reverse (211312202001), we get a palindrome (311514415113).
The spelling of 100202213112 in words is "one hundred billion, two hundred two million, two hundred thirteen thousand, one hundred twelve".
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