Base | Representation |
---|---|
bin | 11101001010011010011… |
… | …10111001101101101011 |
3 | 10112210101201022011212021 |
4 | 32211031032321231223 |
5 | 112404120410211021 |
6 | 2044153441125311 |
7 | 132252032043046 |
oct | 16451516715553 |
9 | 3483351264767 |
10 | 1002023132011 |
11 | 356a56a31a20 |
12 | 142247629837 |
13 | 7364b481a85 |
14 | 366d9003c5d |
15 | 1b0e9197c41 |
hex | e94d3b9b6b |
1002023132011 has 4 divisors (see below), whose sum is σ = 1093116144024. Its totient is φ = 910930120000.
The previous prime is 1002023131973. The next prime is 1002023132041. The reversal of 1002023132011 is 1102313202001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1002023132011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1002023132041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45546505990 + ... + 45546506011.
It is an arithmetic number, because the mean of its divisors is an integer number (273279036006).
Almost surely, 21002023132011 is an apocalyptic number.
1002023132011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1002023132011 is a deficient number, since it is larger than the sum of its proper divisors (91093012013).
1002023132011 is an equidigital number, since it uses as much as digits as its factorization.
1002023132011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91093012012.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1002023132011 its reverse (1102313202001), we get a palindrome (2104336334012).
The spelling of 1002023132011 in words is "one trillion, two billion, twenty-three million, one hundred thirty-two thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •