Base | Representation |
---|---|
bin | 11101001010100011101… |
… | …00100101101000111111 |
3 | 10112210121002011120200222 |
4 | 32211101310211220333 |
5 | 112404300112321002 |
6 | 2044205231211555 |
7 | 132253655323151 |
oct | 16452164455077 |
9 | 3483532146628 |
10 | 1002100120127 |
11 | 356a96436267 |
12 | 142269376bbb |
13 | 736613c9282 |
14 | 36705324ad1 |
15 | 1b100d041a2 |
hex | e951d25a3f |
1002100120127 has 2 divisors, whose sum is σ = 1002100120128. Its totient is φ = 1002100120126.
The previous prime is 1002100120123. The next prime is 1002100120247. The reversal of 1002100120127 is 7210210012001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1002100120127 - 22 = 1002100120123 is a prime.
It is a super-2 number, since 2×10021001201272 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1002100120121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501050060063 + 501050060064.
It is an arithmetic number, because the mean of its divisors is an integer number (501050060064).
Almost surely, 21002100120127 is an apocalyptic number.
1002100120127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002100120127 is an equidigital number, since it uses as much as digits as its factorization.
1002100120127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 1002100120127 its reverse (7210210012001), we get a palindrome (8212310132128).
The spelling of 1002100120127 in words is "one trillion, two billion, one hundred million, one hundred twenty thousand, one hundred twenty-seven".
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