Base | Representation |
---|---|
bin | 101110101010011111… |
… | …1101000100010000001 |
3 | 100120122211012101001222 |
4 | 1131110333220202001 |
5 | 3120212303340131 |
6 | 114011432404425 |
7 | 10145205526226 |
oct | 1352477504201 |
9 | 316584171058 |
10 | 100210215041 |
11 | 39554065842 |
12 | 17508246715 |
13 | 95b0232441 |
14 | 4bc8d4194d |
15 | 291791087b |
hex | 1754fe8881 |
100210215041 has 2 divisors, whose sum is σ = 100210215042. Its totient is φ = 100210215040.
The previous prime is 100210215023. The next prime is 100210215043. The reversal of 100210215041 is 140512012001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59002839025 + 41207376016 = 242905^2 + 202996^2 .
It is a cyclic number.
It is not a de Polignac number, because 100210215041 - 210 = 100210214017 is a prime.
Together with 100210215043, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (100210215043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50105107520 + 50105107521.
It is an arithmetic number, because the mean of its divisors is an integer number (50105107521).
Almost surely, 2100210215041 is an apocalyptic number.
It is an amenable number.
100210215041 is a deficient number, since it is larger than the sum of its proper divisors (1).
100210215041 is an equidigital number, since it uses as much as digits as its factorization.
100210215041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 100210215041 its reverse (140512012001), we get a palindrome (240722227042).
The spelling of 100210215041 in words is "one hundred billion, two hundred ten million, two hundred fifteen thousand, forty-one".
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