Base | Representation |
---|---|
bin | 10010101010101000… |
… | …10101110001101111 |
3 | 221212101220022102112 |
4 | 21111110111301233 |
5 | 131010430030111 |
6 | 4334223514235 |
7 | 503223620426 |
oct | 112524256157 |
9 | 27771808375 |
10 | 10021330031 |
11 | 4282863639 |
12 | 1b3815897b |
13 | c392480ab |
14 | 6b0d162bd |
15 | 3d9bc2e8b |
hex | 255515c6f |
10021330031 has 2 divisors, whose sum is σ = 10021330032. Its totient is φ = 10021330030.
The previous prime is 10021330019. The next prime is 10021330043. The reversal of 10021330031 is 13003312001.
It is a balanced prime because it is at equal distance from previous prime (10021330019) and next prime (10021330043).
It is a cyclic number.
It is not a de Polignac number, because 10021330031 - 218 = 10021067887 is a prime.
It is a super-3 number, since 3×100213300313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 10021329988 and 10021330015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10021330091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010665015 + 5010665016.
It is an arithmetic number, because the mean of its divisors is an integer number (5010665016).
Almost surely, 210021330031 is an apocalyptic number.
10021330031 is a deficient number, since it is larger than the sum of its proper divisors (1).
10021330031 is an equidigital number, since it uses as much as digits as its factorization.
10021330031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 10021330031 its reverse (13003312001), we get a palindrome (23024642032).
The spelling of 10021330031 in words is "ten billion, twenty-one million, three hundred thirty thousand, thirty-one".
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