100214032013 has 2 divisors, whose sum is σ = 100214032014. Its totient is φ = 100214032012.

The previous prime is 100214031991. The next prime is 100214032027. The reversal of 100214032013 is 310230412001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87135364969 + 13078667044 = 295187^2 + 114362^2 .

It is an emirp because it is prime and its reverse (310230412001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100214032013 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 100214031982 and 100214032000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100214032063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50107016006 + 50107016007.

It is an arithmetic number, because the mean of its divisors is an integer number (50107016007).

Almost surely, 2^100214032013 is an apocalyptic number.

It is an amenable number.

100214032013 is a deficient number, since it is larger than the sum of its proper divisors (1).

100214032013 is an equidigital number, since it uses as much as digits as its factorization.

100214032013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 100214032013 its reverse (310230412001), we get a palindrome (410444444014).

The spelling of 100214032013 in words is "one hundred billion, two hundred fourteen million, thirty-two thousand, thirteen".