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1002200311141 is a prime number
BaseRepresentation
bin11101001010101111100…
…10110010010101100101
310112210212001200210221021
432211113302302111211
5112410001234424031
62044223210451141
7132256313042221
oct16452762622545
93483761623837
101002200311141
11357037a48257
12142296a33ab1
13736790a89b3
1436714765781
151b1099e5511
hexe957cb2565

1002200311141 has 2 divisors, whose sum is σ = 1002200311142. Its totient is φ = 1002200311140.

The previous prime is 1002200311139. The next prime is 1002200311153. The reversal of 1002200311141 is 1411130022001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 884634302500 + 117566008641 = 940550^2 + 342879^2 .

It is a cyclic number.

It is not a de Polignac number, because 1002200311141 - 21 = 1002200311139 is a prime.

It is a super-2 number, since 2×10022003111412 (a number of 25 digits) contains 22 as substring.

Together with 1002200311139, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002200311111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501100155570 + 501100155571.

It is an arithmetic number, because the mean of its divisors is an integer number (501100155571).

Almost surely, 21002200311141 is an apocalyptic number.

It is an amenable number.

1002200311141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002200311141 is an equidigital number, since it uses as much as digits as its factorization.

1002200311141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1002200311141 its reverse (1411130022001), we get a palindrome (2413330333142).

The spelling of 1002200311141 in words is "one trillion, two billion, two hundred million, three hundred eleven thousand, one hundred forty-one".