1002201220213 has 2 divisors, whose sum is σ = 1002201220214. Its totient is φ = 1002201220212.

The previous prime is 1002201220187. The next prime is 1002201220249. The reversal of 1002201220213 is 3120221022001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 999116195364 + 3085024849 = 999558^2 + 55543^2 .

It is an emirp because it is prime and its reverse (3120221022001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1002201220213 is a prime.

It is a super-2 number, since 2×1002201220213² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002201229213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501100610106 + 501100610107.

It is an arithmetic number, because the mean of its divisors is an integer number (501100610107).

Almost surely, 2^{1002201220213} is an apocalyptic number.

It is an amenable number.

1002201220213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002201220213 is an equidigital number, since it uses as much as digits as its factorization.

1002201220213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 1002201220213 its reverse (3120221022001), we get a palindrome (4122422242214).

The spelling of 1002201220213 in words is "one trillion, two billion, two hundred one million, two hundred twenty thousand, two hundred thirteen".