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100240053 = 333413351
BaseRepresentation
bin1011111100110…
…00101010110101
320222121201111120
411332120222311
5201130140203
613540254153
72325012024
oct576305265
9228551446
10100240053
1151645921
12296a1359
13179c8b54
14d4548bb
158c00b53
hex5f98ab5

100240053 has 4 divisors (see below), whose sum is σ = 133653408. Its totient is φ = 66826700.

The previous prime is 100240033. The next prime is 100240069. The reversal of 100240053 is 350042001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100240053 - 29 = 100239541 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100240033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16706673 + ... + 16706678.

It is an arithmetic number, because the mean of its divisors is an integer number (33413352).

Almost surely, 2100240053 is an apocalyptic number.

It is an amenable number.

100240053 is a deficient number, since it is larger than the sum of its proper divisors (33413355).

100240053 is an equidigital number, since it uses as much as digits as its factorization.

100240053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33413354.

The product of its (nonzero) digits is 120, while the sum is 15.

The square root of 100240053 is about 10011.9954554524. The cubic root of 100240053 is about 464.5299956722.

Adding to 100240053 its reverse (350042001), we get a palindrome (450282054).

The spelling of 100240053 in words is "one hundred million, two hundred forty thousand, fifty-three".

Divisors: 1 3 33413351 100240053