Base | Representation |
---|---|
bin | 10010101010111101… |
… | …00100011000110000 |
3 | 221212120221112110020 |
4 | 21111132210120300 |
5 | 131012121330222 |
6 | 4334401203440 |
7 | 503255455530 |
oct | 112536443060 |
9 | 27776845406 |
10 | 10024011312 |
11 | 4284325077 |
12 | 1b39030580 |
13 | c39976653 |
14 | 6b14134c0 |
15 | 3da05265c |
hex | 2557a4630 |
10024011312 has 80 divisors (see below), whose sum is σ = 29606795520. Its totient is φ = 2862832896.
The previous prime is 10024011281. The next prime is 10024011313. The reversal of 10024011312 is 21311042001.
It is a super-2 number, since 2×100240113122 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10024011291 and 10024011300.
It is not an unprimeable number, because it can be changed into a prime (10024011313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1134303 + ... + 1143105.
It is an arithmetic number, because the mean of its divisors is an integer number (370084944).
Almost surely, 210024011312 is an apocalyptic number.
10024011312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
10024011312 is an abundant number, since it is smaller than the sum of its proper divisors (19582784208).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10024011312 is a wasteful number, since it uses less digits than its factorization.
10024011312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12210 (or 12204 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 10024011312 its reverse (21311042001), we get a palindrome (31335053313).
The spelling of 10024011312 in words is "ten billion, twenty-four million, eleven thousand, three hundred twelve".
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