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10024310213 is a prime number
BaseRepresentation
bin10010101010111111…
…01101010111000101
3221212121111201110122
421111133231113011
5131012210411323
64334411431325
7503261142131
oct112537552705
927777451418
1010024310213
1142845096a5
121b39155545
13c39a4c708
146b14903c1
153da0b0ec8
hex2557ed5c5

10024310213 has 2 divisors, whose sum is σ = 10024310214. Its totient is φ = 10024310212.

The previous prime is 10024310209. The next prime is 10024310221. The reversal of 10024310213 is 31201342001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6538824769 + 3485485444 = 80863^2 + 59038^2 .

It is a cyclic number.

It is not a de Polignac number, because 10024310213 - 22 = 10024310209 is a prime.

It is a super-2 number, since 2×100243102132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10024310191 and 10024310200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10024310203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012155106 + 5012155107.

It is an arithmetic number, because the mean of its divisors is an integer number (5012155107).

Almost surely, 210024310213 is an apocalyptic number.

It is an amenable number.

10024310213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10024310213 is an equidigital number, since it uses as much as digits as its factorization.

10024310213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10024310213 its reverse (31201342001), we get a palindrome (41225652214).

The spelling of 10024310213 in words is "ten billion, twenty-four million, three hundred ten thousand, two hundred thirteen".