10024401113 has 2 divisors, whose sum is σ = 10024401114. Its totient is φ = 10024401112.

The previous prime is 10024401031. The next prime is 10024401119. The reversal of 10024401113 is 31110442001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8202562624 + 1821838489 = 90568^2 + 42683^2 .

It is an emirp because it is prime and its reverse (31110442001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10024401113 - 2⁸ = 10024400857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10024401091 and 10024401100.

It is not a weakly prime, because it can be changed into another prime (10024401119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012200556 + 5012200557.

It is an arithmetic number, because the mean of its divisors is an integer number (5012200557).

Almost surely, 2^10024401113 is an apocalyptic number.

It is an amenable number.

10024401113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10024401113 is an equidigital number, since it uses as much as digits as its factorization.

10024401113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 10024401113 its reverse (31110442001), we get a palindrome (41134843114).

The spelling of 10024401113 in words is "ten billion, twenty-four million, four hundred one thousand, one hundred thirteen".