100250056031 has 4 divisors (see below), whose sum is σ = 101746325592. Its totient is φ = 98753786472.

The previous prime is 100250056021. The next prime is 100250056037. The reversal of 100250056031 is 130650052001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100250056031 - 2¹⁰ = 100250055007 is a prime.

It is a super-3 number, since 3×100250056031³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100250055988 and 100250056006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100250056037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 748134680 + ... + 748134813.

It is an arithmetic number, because the mean of its divisors is an integer number (25436581398).

Almost surely, 2^100250056031 is an apocalyptic number.

100250056031 is a deficient number, since it is larger than the sum of its proper divisors (1496269561).

100250056031 is an equidigital number, since it uses as much as digits as its factorization.

100250056031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1496269560.

The product of its (nonzero) digits is 900, while the sum is 23.

The spelling of 100250056031 in words is "one hundred billion, two hundred fifty million, fifty-six thousand, thirty-one".