10030555223115 has 48 divisors (see below), whose sum is σ = 18669519095040. Its totient is φ = 4585297429440.

The previous prime is 10030555223113. The next prime is 10030555223167. The reversal of 10030555223115 is 51132255503001.

It is a happy number.

It is not a de Polignac number, because 10030555223115 - 2¹ = 10030555223113 is a prime.

It is a super-3 number, since 3×10030555223115³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (10030555223113) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 42019266 + ... + 42257304.

It is an arithmetic number, because the mean of its divisors is an integer number (388948314480).

Almost surely, 2^{10030555223115} is an apocalyptic number.

10030555223115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

10030555223115 is a deficient number, since it is larger than the sum of its proper divisors (8638963871925).

10030555223115 is a wasteful number, since it uses less digits than its factorization.

10030555223115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 295392 (or 295385 counting only the distinct ones).

The product of its (nonzero) digits is 22500, while the sum is 33.

The spelling of 10030555223115 in words is "ten trillion, thirty billion, five hundred fifty-five million, two hundred twenty-three thousand, one hundred fifteen".