Base | Representation |
---|---|
bin | 101110101101011110… |
… | …0010101010101000101 |
3 | 100120220202222122111001 |
4 | 1131122330111111011 |
5 | 3120413330411003 |
6 | 114025355413301 |
7 | 10150530021142 |
oct | 1353274252505 |
9 | 316822878431 |
10 | 100310013253 |
11 | 395a54296aa |
12 | 17535754231 |
13 | 95c7b05138 |
14 | 4bd82bd3c9 |
15 | 292157561d |
hex | 175af15545 |
100310013253 has 2 divisors, whose sum is σ = 100310013254. Its totient is φ = 100310013252.
The previous prime is 100310013211. The next prime is 100310013257. The reversal of 100310013253 is 352310013001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 63568024129 + 36741989124 = 252127^2 + 191682^2 .
It is a cyclic number.
It is not a de Polignac number, because 100310013253 - 29 = 100310012741 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100310013253.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100310013257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50155006626 + 50155006627.
It is an arithmetic number, because the mean of its divisors is an integer number (50155006627).
Almost surely, 2100310013253 is an apocalyptic number.
It is an amenable number.
100310013253 is a deficient number, since it is larger than the sum of its proper divisors (1).
100310013253 is an equidigital number, since it uses as much as digits as its factorization.
100310013253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 19.
Adding to 100310013253 its reverse (352310013001), we get a palindrome (452620026254).
The spelling of 100310013253 in words is "one hundred billion, three hundred ten million, thirteen thousand, two hundred fifty-three".
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