10031102113 has 4 divisors (see below), whose sum is σ = 10032542740. Its totient is φ = 10029661488.

The previous prime is 10031102101. The next prime is 10031102119. The reversal of 10031102113 is 31120113001.

10031102113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31120113001 = 170801 ⋅182201.

It can be written as a sum of positive squares in 2 ways, for example, as 2820884544 + 7210217569 = 53112^2 + 84913^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10031102113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10031102093 and 10031102102.

It is not an unprimeable number, because it can be changed into a prime (10031102119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 709818 + ... + 723811.

It is an arithmetic number, because the mean of its divisors is an integer number (2508135685).

Almost surely, 2^10031102113 is an apocalyptic number.

It is an amenable number.

10031102113 is a deficient number, since it is larger than the sum of its proper divisors (1440627).

10031102113 is an equidigital number, since it uses as much as digits as its factorization.

10031102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1440626.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10031102113 its reverse (31120113001), we get a palindrome (41151215114).

The spelling of 10031102113 in words is "ten billion, thirty-one million, one hundred two thousand, one hundred thirteen".