10031130020221 has 2 divisors, whose sum is σ = 10031130020222. Its totient is φ = 10031130020220.

The previous prime is 10031130020213. The next prime is 10031130020227. The reversal of 10031130020221 is 12202003113001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9632419860996 + 398710159225 = 3103614^2 + 631435^2 .

It is a cyclic number.

It is not a de Polignac number, because 10031130020221 - 2³ = 10031130020213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10031130020195 and 10031130020204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10031130020227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015565010110 + 5015565010111.

It is an arithmetic number, because the mean of its divisors is an integer number (5015565010111).

Almost surely, 2^{10031130020221} is an apocalyptic number.

It is an amenable number.

10031130020221 is a deficient number, since it is larger than the sum of its proper divisors (1).

10031130020221 is an equidigital number, since it uses as much as digits as its factorization.

10031130020221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10031130020221 its reverse (12202003113001), we get a palindrome (22233133133222).

The spelling of 10031130020221 in words is "ten trillion, thirty-one billion, one hundred thirty million, twenty thousand, two hundred twenty-one".