Base | Representation |
---|---|
bin | 111011110010101… |
… | …000101001001111 |
3 | 2120220120020212121 |
4 | 323302220221033 |
5 | 4023300120143 |
6 | 243312313411 |
7 | 33600313402 |
oct | 7362505117 |
9 | 2526506777 |
10 | 1003129423 |
11 | 475270a8a |
12 | 23bb42867 |
13 | 12ca9470a |
14 | 97323d39 |
15 | 5d0ed7ed |
hex | 3bca8a4f |
1003129423 has 2 divisors, whose sum is σ = 1003129424. Its totient is φ = 1003129422.
The previous prime is 1003129381. The next prime is 1003129433. The reversal of 1003129423 is 3249213001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1003129423 is a prime.
It is a super-3 number, since 3×10031294233 (a number of 28 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1003129433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501564711 + 501564712.
It is an arithmetic number, because the mean of its divisors is an integer number (501564712).
Almost surely, 21003129423 is an apocalyptic number.
1003129423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003129423 is an equidigital number, since it uses as much as digits as its factorization.
1003129423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
The square root of 1003129423 is about 31672.2184729772. The cubic root of 1003129423 is about 1001.0420547447.
The spelling of 1003129423 in words is "one billion, three million, one hundred twenty-nine thousand, four hundred twenty-three".
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