Base | Representation |
---|---|
bin | 101110101101100110… |
… | …1001110001011101111 |
3 | 100120221002022120102121 |
4 | 1131123031032023233 |
5 | 3120420444043211 |
6 | 114030034333411 |
7 | 10150612450312 |
oct | 1353315161357 |
9 | 316832276377 |
10 | 100314440431 |
11 | 395a7982927 |
12 | 1753712a267 |
13 | 95c89c527a |
14 | 4bd8b12979 |
15 | 2921b4c271 |
hex | 175b34e2ef |
100314440431 has 2 divisors, whose sum is σ = 100314440432. Its totient is φ = 100314440430.
The previous prime is 100314440399. The next prime is 100314440437. The reversal of 100314440431 is 134044413001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100314440431 - 25 = 100314440399 is a prime.
It is a super-2 number, since 2×1003144404312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100314440396 and 100314440405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100314440437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50157220215 + 50157220216.
It is an arithmetic number, because the mean of its divisors is an integer number (50157220216).
Almost surely, 2100314440431 is an apocalyptic number.
100314440431 is a deficient number, since it is larger than the sum of its proper divisors (1).
100314440431 is an equidigital number, since it uses as much as digits as its factorization.
100314440431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 100314440431 its reverse (134044413001), we get a palindrome (234358853432).
The spelling of 100314440431 in words is "one hundred billion, three hundred fourteen million, four hundred forty thousand, four hundred thirty-one".
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