1003152145045 has 4 divisors (see below), whose sum is σ = 1203782574060. Its totient is φ = 802521716032.

The previous prime is 1003152145007. The next prime is 1003152145063. The reversal of 1003152145045 is 5405412513001.

1003152145045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 171178305169 + 831973839876 = 413737^2 + 912126^2 .

It is a cyclic number.

It is not a de Polignac number, because 1003152145045 - 2³⁷ = 865713191573 is a prime.

It is a super-2 number, since 2×1003152145045² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1003152144998 and 1003152145016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100315214500 + ... + 100315214509.

It is an arithmetic number, because the mean of its divisors is an integer number (300945643515).

Almost surely, 2^{1003152145045} is an apocalyptic number.

It is an amenable number.

1003152145045 is a deficient number, since it is larger than the sum of its proper divisors (200630429015).

1003152145045 is an equidigital number, since it uses as much as digits as its factorization.

1003152145045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200630429014.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 1003152145045 its reverse (5405412513001), we get a palindrome (6408564658046).

The spelling of 1003152145045 in words is "one trillion, three billion, one hundred fifty-two million, one hundred forty-five thousand, forty-five".