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10032011303 = 47383557303
BaseRepresentation
bin10010101011111010…
…00101100000100111
3221220010222222101012
421111331011200213
5131021143330203
64335244452435
7503413455236
oct112575054047
927803888335
1010032011303
114288899636
121b3b84a11b
13c3b517a82
146b24d6b1d
153daad2bd8
hex255f45827

10032011303 has 8 divisors (see below), whose sum is σ = 10272227328. Its totient is φ = 9792910744.

The previous prime is 10032011273. The next prime is 10032011329. The reversal of 10032011303 is 30311023001.

10032011303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10032011303 - 218 = 10031749159 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10032019303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 260651 + ... + 296652.

It is an arithmetic number, because the mean of its divisors is an integer number (1284028416).

Almost surely, 210032011303 is an apocalyptic number.

10032011303 is a deficient number, since it is larger than the sum of its proper divisors (240216025).

10032011303 is an equidigital number, since it uses as much as digits as its factorization.

10032011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 557733.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 10032011303 its reverse (30311023001), we get a palindrome (40343034304).

The spelling of 10032011303 in words is "ten billion, thirty-two million, eleven thousand, three hundred three".

Divisors: 1 47 383 18001 557303 26193241 213447049 10032011303