1003201132013 has 8 divisors (see below), whose sum is σ = 1028114235456. Its totient is φ = 978309208800.

The previous prime is 1003201131991. The next prime is 1003201132051. The reversal of 1003201132013 is 3102311023001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1003201132013 is a prime.

It is a super-2 number, since 2×1003201132013² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1003201131982 and 1003201132000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1003201132093) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5199131 + ... + 5388632.

It is an arithmetic number, because the mean of its divisors is an integer number (128514279432).

Almost surely, 2^{1003201132013} is an apocalyptic number.

It is an amenable number.

1003201132013 is a deficient number, since it is larger than the sum of its proper divisors (24913103443).

1003201132013 is a wasteful number, since it uses less digits than its factorization.

1003201132013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10590115.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1003201132013 its reverse (3102311023001), we get a palindrome (4105512155014).

The spelling of 1003201132013 in words is "one trillion, three billion, two hundred one million, one hundred thirty-two thousand, thirteen".