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100320132023 is a prime number
BaseRepresentation
bin101110101101110001…
…0111011101110110111
3100120221111000201211022
41131123202323232313
53120423423211043
6114030400331355
710151012024006
oct1353342735667
9316844021738
10100320132023
1139600110021
1217539013b5b
1395c9c38a87
144bd9794c3d
1529223c3868
hex175b8bbbb7

100320132023 has 2 divisors, whose sum is σ = 100320132024. Its totient is φ = 100320132022.

The previous prime is 100320132007. The next prime is 100320132067. The reversal of 100320132023 is 320231023001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100320132023 - 24 = 100320132007 is a prime.

It is a super-2 number, since 2×1003201320232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100320131992 and 100320132010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100320137023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50160066011 + 50160066012.

It is an arithmetic number, because the mean of its divisors is an integer number (50160066012).

Almost surely, 2100320132023 is an apocalyptic number.

100320132023 is a deficient number, since it is larger than the sum of its proper divisors (1).

100320132023 is an equidigital number, since it uses as much as digits as its factorization.

100320132023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 100320132023 its reverse (320231023001), we get a palindrome (420551155024).

The spelling of 100320132023 in words is "one hundred billion, three hundred twenty million, one hundred thirty-two thousand, twenty-three".