Base | Representation |
---|---|
bin | 11101001100101011100… |
… | …01101001011110110001 |
3 | 10112220112112102122102122 |
4 | 32212111301221132301 |
5 | 112414113442400423 |
6 | 2044514315124025 |
7 | 132324140666414 |
oct | 16462561513661 |
9 | 3486475378378 |
10 | 1003240200113 |
11 | 357520a36228 |
12 | 142527143615 |
13 | 737b3671008 |
14 | 367b28d7b7b |
15 | 1b16ae558c8 |
hex | e995c697b1 |
1003240200113 has 2 divisors, whose sum is σ = 1003240200114. Its totient is φ = 1003240200112.
The previous prime is 1003240200031. The next prime is 1003240200119. The reversal of 1003240200113 is 3110020423001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 949556700304 + 53683499809 = 974452^2 + 231697^2 .
It is a cyclic number.
It is not a de Polignac number, because 1003240200113 - 230 = 1002166458289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1003240200091 and 1003240200100.
It is not a weakly prime, because it can be changed into another prime (1003240200119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501620100056 + 501620100057.
It is an arithmetic number, because the mean of its divisors is an integer number (501620100057).
Almost surely, 21003240200113 is an apocalyptic number.
It is an amenable number.
1003240200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003240200113 is an equidigital number, since it uses as much as digits as its factorization.
1003240200113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1003240200113 its reverse (3110020423001), we get a palindrome (4113260623114).
The spelling of 1003240200113 in words is "one trillion, three billion, two hundred forty million, two hundred thousand, one hundred thirteen".
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