Base | Representation |
---|---|
bin | 11101001100101011100… |
… | …01101001011101011111 |
3 | 10112220112112102122022121 |
4 | 32212111301221131133 |
5 | 112414113442400111 |
6 | 2044514315123411 |
7 | 132324140666236 |
oct | 16462561513537 |
9 | 3486475378277 |
10 | 1003240200031 |
11 | 357520a36163 |
12 | 142527143567 |
13 | 737b3670c74 |
14 | 367b28d7b1d |
15 | 1b16ae55871 |
hex | e995c6975f |
1003240200031 has 2 divisors, whose sum is σ = 1003240200032. Its totient is φ = 1003240200030.
The previous prime is 1003240199989. The next prime is 1003240200113. The reversal of 1003240200031 is 1300020423001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1003240200031 - 27 = 1003240199903 is a prime.
It is a super-2 number, since 2×10032402000312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1003240199978 and 1003240200014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1003240200331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501620100015 + 501620100016.
It is an arithmetic number, because the mean of its divisors is an integer number (501620100016).
Almost surely, 21003240200031 is an apocalyptic number.
1003240200031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003240200031 is an equidigital number, since it uses as much as digits as its factorization.
1003240200031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 1003240200031 its reverse (1300020423001), we get a palindrome (2303260623032).
The spelling of 1003240200031 in words is "one trillion, three billion, two hundred forty million, two hundred thousand, thirty-one".
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