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10032410013 = 33344136671
BaseRepresentation
bin10010101011111101…
…00110110110011101
3221220011202020022020
421111332212312131
5131021244110023
64335301210353
7503420035533
oct112576466635
927804666266
1010032410013
11428904114a
121b3ba009b9
13c3b6273b2
146b259c153
153dab60de3
hex255fa6d9d

10032410013 has 4 divisors (see below), whose sum is σ = 13376546688. Its totient is φ = 6688273340.

The previous prime is 10032410009. The next prime is 10032410033. The reversal of 10032410013 is 31001423001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10032410013 - 22 = 10032410009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10032409974 and 10032410001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10032410033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672068333 + ... + 1672068338.

It is an arithmetic number, because the mean of its divisors is an integer number (3344136672).

Almost surely, 210032410013 is an apocalyptic number.

It is an amenable number.

10032410013 is a deficient number, since it is larger than the sum of its proper divisors (3344136675).

10032410013 is an equidigital number, since it uses as much as digits as its factorization.

10032410013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3344136674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 10032410013 its reverse (31001423001), we get a palindrome (41033833014).

The spelling of 10032410013 in words is "ten billion, thirty-two million, four hundred ten thousand, thirteen".

Divisors: 1 3 3344136671 10032410013