Base | Representation |
---|---|
bin | 10010101100000001… |
… | …10111101000101001 |
3 | 221220012212100210112 |
4 | 21112000313220221 |
5 | 131021422044144 |
6 | 4335322024105 |
7 | 503425055516 |
oct | 112600675051 |
9 | 27805770715 |
10 | 10033003049 |
11 | 4289406763 |
12 | 1b40048035 |
13 | c3b7a42c4 |
14 | 6b26b430d |
15 | 3dac2b99e |
hex | 256037a29 |
10033003049 has 2 divisors, whose sum is σ = 10033003050. Its totient is φ = 10033003048.
The previous prime is 10033003007. The next prime is 10033003051. The reversal of 10033003049 is 94030033001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8980973824 + 1052029225 = 94768^2 + 32435^2 .
It is a cyclic number.
It is not a de Polignac number, because 10033003049 - 232 = 5738035753 is a prime.
It is a super-2 number, since 2×100330030492 (a number of 21 digits) contains 22 as substring.
Together with 10033003051, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10033003069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016501524 + 5016501525.
It is an arithmetic number, because the mean of its divisors is an integer number (5016501525).
Almost surely, 210033003049 is an apocalyptic number.
It is an amenable number.
10033003049 is a deficient number, since it is larger than the sum of its proper divisors (1).
10033003049 is an equidigital number, since it uses as much as digits as its factorization.
10033003049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
The spelling of 10033003049 in words is "ten billion, thirty-three million, three thousand, forty-nine".
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