10033101000119 has 2 divisors, whose sum is σ = 10033101000120. Its totient is φ = 10033101000118.

The previous prime is 10033100999983. The next prime is 10033101000121. The reversal of 10033101000119 is 91100010133001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10033101000119 - 2⁸ = 10033100999863 is a prime.

It is a super-2 number, since 2×10033101000119² (a number of 27 digits) contains 22 as substring.

Together with 10033101000121, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10033101000119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10033101000199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016550500059 + 5016550500060.

It is an arithmetic number, because the mean of its divisors is an integer number (5016550500060).

Almost surely, 2^{10033101000119} is an apocalyptic number.

10033101000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10033101000119 is an equidigital number, since it uses as much as digits as its factorization.

10033101000119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 10033101000119 in words is "ten trillion, thirty-three billion, one hundred one million, one hundred nineteen", and thus it is an aban number.