10034113 has 2 divisors, whose sum is σ = 10034114. Its totient is φ = 10034112.

The previous prime is 10034083. The next prime is 10034149. The reversal of 10034113 is 31143001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9048064 + 986049 = 3008^2 + 993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10034113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10034093 and 10034102.

It is not a weakly prime, because it can be changed into another prime (10031113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017056 + 5017057.

It is an arithmetic number, because the mean of its divisors is an integer number (5017057).

Almost surely, 2^10034113 is an apocalyptic number.

It is an amenable number.

10034113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10034113 is an equidigital number, since it uses as much as digits as its factorization.

10034113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 10034113 is about 3167.6668069732. Note that the first 3 decimals coincide. The cubic root of 10034113 is about 215.6881717309.

Adding to 10034113 its reverse (31143001), we get a palindrome (41177114).

The spelling of 10034113 in words is "ten million, thirty-four thousand, one hundred thirteen".