1003412013 has 4 divisors (see below), whose sum is σ = 1337882688. Its totient is φ = 668941340.

The previous prime is 1003411993. The next prime is 1003412027. The reversal of 1003412013 is 3102143001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3102143001 = 3 ⋅1034047667.

It is a cyclic number.

It is not a de Polignac number, because 1003412013 - 2²¹ = 1001314861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1003411983 and 1003412001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1003410013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167235333 + ... + 167235338.

It is an arithmetic number, because the mean of its divisors is an integer number (334470672).

Almost surely, 2^1003412013 is an apocalyptic number.

It is an amenable number.

1003412013 is a deficient number, since it is larger than the sum of its proper divisors (334470675).

1003412013 is an equidigital number, since it uses as much as digits as its factorization.

1003412013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334470674.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 1003412013 is about 31676.6793240706. The cubic root of 1003412013 is about 1001.1360465761.

Adding to 1003412013 its reverse (3102143001), we get a palindrome (4105555014).

The spelling of 1003412013 in words is "one billion, three million, four hundred twelve thousand, thirteen".