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100400134103 = 947106019149
BaseRepresentation
bin101110110000001010…
…0000111011111010111
3100121011001120021001022
41131200110013133113
53121104413242403
6114042335151355
710153003026143
oct1354024073727
9317131507038
10100400134103
1139641292845
121755b97555b
13961069a099
144c0625c223
152929427d38
hex17605077d7

100400134103 has 4 divisors (see below), whose sum is σ = 100506154200. Its totient is φ = 100294114008.

The previous prime is 100400134091. The next prime is 100400134117. The reversal of 100400134103 is 301431004001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100400134103 - 212 = 100400130007 is a prime.

It is a super-2 number, since 2×1004001341032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100400131103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53008628 + ... + 53010521.

It is an arithmetic number, because the mean of its divisors is an integer number (25126538550).

Almost surely, 2100400134103 is an apocalyptic number.

100400134103 is a deficient number, since it is larger than the sum of its proper divisors (106020097).

100400134103 is an equidigital number, since it uses as much as digits as its factorization.

100400134103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106020096.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 100400134103 its reverse (301431004001), we get a palindrome (401831138104).

The spelling of 100400134103 in words is "one hundred billion, four hundred million, one hundred thirty-four thousand, one hundred three".

Divisors: 1 947 106019149 100400134103