1004011413213 has 4 divisors (see below), whose sum is σ = 1338681884288. Its totient is φ = 669340942140.

The previous prime is 1004011413199. The next prime is 1004011413227. The reversal of 1004011413213 is 3123141104001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1004011413199) and next prime (1004011413227).

It is not a de Polignac number, because 1004011413213 - 2¹⁸ = 1004011151069 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1004011413213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004011413253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167335235533 + ... + 167335235538.

It is an arithmetic number, because the mean of its divisors is an integer number (334670471072).

Almost surely, 2^{1004011413213} is an apocalyptic number.

It is an amenable number.

1004011413213 is a deficient number, since it is larger than the sum of its proper divisors (334670471075).

1004011413213 is an equidigital number, since it uses as much as digits as its factorization.

1004011413213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 334670471074.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1004011413213 its reverse (3123141104001), we get a palindrome (4127152517214).

The spelling of 1004011413213 in words is "one trillion, four billion, eleven million, four hundred thirteen thousand, two hundred thirteen".