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1004014205981 is a prime number
BaseRepresentation
bin11101001110000111110…
…10001111110000011101
310112222112110212012212122
432213003322033300131
5112422210114042411
62045123204512325
7132352256640323
oct16470372176035
93488473765778
101004014205981
113578889322a6
121427023ab6a5
13738a7b22357
1436847617d13
151b1b3d959db
hexe9c3e8fc1d

1004014205981 has 2 divisors, whose sum is σ = 1004014205982. Its totient is φ = 1004014205980.

The previous prime is 1004014205969. The next prime is 1004014206007. The reversal of 1004014205981 is 1895024104001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 908906729956 + 95107476025 = 953366^2 + 308395^2 .

It is a cyclic number.

It is not a de Polignac number, because 1004014205981 - 230 = 1002940464157 is a prime.

It is a super-2 number, since 2×10040142059812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1004014205921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502007102990 + 502007102991.

It is an arithmetic number, because the mean of its divisors is an integer number (502007102991).

Almost surely, 21004014205981 is an apocalyptic number.

It is an amenable number.

1004014205981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1004014205981 is an equidigital number, since it uses as much as digits as its factorization.

1004014205981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 35.

Adding to 1004014205981 its reverse (1895024104001), we get a palindrome (2899038309982).

The spelling of 1004014205981 in words is "one trillion, four billion, fourteen million, two hundred five thousand, nine hundred eighty-one".