Base | Representation |
---|---|
bin | 11101001110001000101… |
… | …01011100111110101111 |
3 | 10112222112222021120012122 |
4 | 32213010111130332233 |
5 | 112422213430304111 |
6 | 2045124021423155 |
7 | 132352404363425 |
oct | 16470425347657 |
9 | 3488488246178 |
10 | 1004021338031 |
11 | 357891963758 |
12 | 14270486aabb |
13 | 738a944b6ba |
14 | 36848553115 |
15 | 1b1b4803cdb |
hex | e9c455cfaf |
1004021338031 has 2 divisors, whose sum is σ = 1004021338032. Its totient is φ = 1004021338030.
The previous prime is 1004021337961. The next prime is 1004021338057. The reversal of 1004021338031 is 1308331204001.
It is an a-pointer prime, because the next prime (1004021338057) can be obtained adding 1004021338031 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1004021338031 - 230 = 1002947596207 is a prime.
It is a super-2 number, since 2×10040213380312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1004021338091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502010669015 + 502010669016.
It is an arithmetic number, because the mean of its divisors is an integer number (502010669016).
Almost surely, 21004021338031 is an apocalyptic number.
1004021338031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004021338031 is an equidigital number, since it uses as much as digits as its factorization.
1004021338031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
The spelling of 1004021338031 in words is "one trillion, four billion, twenty-one million, three hundred thirty-eight thousand, thirty-one".
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