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100404011413 is a prime number
BaseRepresentation
bin101110110000010001…
…0111010000110010101
3100121011022212020201101
41131200202322012111
53121111411331123
6114042554230101
710153051005226
oct1354042720625
9317138766641
10100404011413
11396434a0932
1217561125331
139611426b54
144c0698b24d
152929941aad
hex17608ba195

100404011413 has 2 divisors, whose sum is σ = 100404011414. Its totient is φ = 100404011412.

The previous prime is 100404011399. The next prime is 100404011443. The reversal of 100404011413 is 314110404001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86252053969 + 14151957444 = 293687^2 + 118962^2 .

It is a cyclic number.

It is not a de Polignac number, because 100404011413 - 213 = 100404003221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100404011443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50202005706 + 50202005707.

It is an arithmetic number, because the mean of its divisors is an integer number (50202005707).

Almost surely, 2100404011413 is an apocalyptic number.

It is an amenable number.

100404011413 is a deficient number, since it is larger than the sum of its proper divisors (1).

100404011413 is an equidigital number, since it uses as much as digits as its factorization.

100404011413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 100404011413 its reverse (314110404001), we get a palindrome (414514415414).

The spelling of 100404011413 in words is "one hundred billion, four hundred four million, eleven thousand, four hundred thirteen".